Question

In a parallelogram ABCD diagonals AC and BD intersect at O and AC= 6.8 cm and BD = 5.6cm . Find the length of OA and OD. step by step explanation please urgent​

Answer 1

Answer:

According to theorm of parallelogram diagonals of parallelogram bisect each other.

So , AO = OC and BO = OD

Hence, BO = 1/2 BD

SO, BC = 6.8 cm

And AO = 1/2 AC

So, AO = 3.4

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More to know -:

Parallelogram -: is a quadrilateral having two pairs of parallel sides.

Properties-:

i) Opposite sides are equal.

ii) Opposite sides are congurent.

iii) Opposite angles are congurent.

iv) Same-Side interior angles (consecutive angles) are supplementary.

v) Each diagonal of a parallelogram separates it into two congruent triangles.

vi) The diagonals of a parallelogram bisect each other.

Answer 2

Answer: OA = 3.4 cm and OD = 2.8 cm

Step-by-step explanation:

❍ Given :-

• AC = 6.8 cm
• BD = 5.6 cm
• Diagonals AC and BD intersect at O

❍ To Find :-

• The length of OA and OD

❍ Solution :-

➸ We know that,

According to theorem of parallelogram, diagonals of parallelogram bisect each other.

Here,

When diagonal AC and BD intersect each other at point O,

Then,

$\sf OA = OC = \frac{1}{2}AD$ and $\sf OB = OD = \frac{1}{2}BD$

Therefore,

$\sf →OA = \frac{1}{2} \times AC$

$\sf →OA = \frac{1}{2} \times 6.8 \: cm$

$\sf →\fbox \green{OA = 3.4 \: cm}$

and

$\sf →OD = \frac{1}{2} \times BD$

$\sf →OD = \frac{1}{2} \times 5.6 \: cm$

$\sf →\fbox \green{OD = 2.8 \: cm}$

Hence the length of OA = 3.4 cm and OD = 2.8 cm.