In a parallelogram ABCD, diagonals AC and BD intersect at o and AC = 12.8 cm and BD = 7.6 cm find the measures of oc and od.
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diagonal of parallelogram bisect each other
oc=(1/2)12.8
oc=6.4
similarly
od=(1/2)7.6
od=3.5
oc=(1/2)12.8
oc=6.4
similarly
od=(1/2)7.6
od=3.5
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Given:
- AC = 12.8 cm
- BD = 7.6 cm
To Find:
- The measures of OC and OD.
Solution:
- From the given data, we get to know that O is the midpoint of parallelogram ABCD because AC and BD are diagonals intersecting each other.
- Therefore, OC =1/2 * AC = AC/2
- Substitute the values in the above formula.
- OC = 12.8/2
- OC = 6.4 cm
- OD = 1/2 * BD = BD/2
- Substitute the values in the above formula.
- OD = 7.6/2
- OD = 3.8 cm
∴ The measures of OC = 6.4 cm and OD = 3.8 cm.
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