Question

In a parallelogram ABCD, diagonals AC and BD intersect at O and AC = 6.8 cm and BD = 5.6 cm. Find the measures of OC and OD

Answer 1

as we know parallelogram diagonal bisect each other so AO=OC,OD=OB
AO+OC=AC=6.8, OB+OD=BD=13.6
AO+OC=6.8 SO OC=3.4CM
AND
OB+OD=13.6 SO OD =6.8CM ans

I hope it help you

Answer 2

hey

here is your answers

as per the therom of parallelogram that the diagnol of a parallelogram bisect each other.

therefore, AO=OC AND BO=OD  

therefore BO=1/2BD

S0,BO=6.8CM  

SIMILARLY AO=1/2AC

SO,AO=3.4

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