Math, asked by roberthood1238, 10 months ago

In a parallelogram ABCD ,E and F are points on DC and AD,if area of triangle BFC is equal to 16 cm square then what is the area of triangle AEB with proof ​

Answers

Answered by stardum73
1

Answer:Area of triangle AEB = 16 cm square

Step-by-step explanation:

Area of triangle BFC = 16cm square

Area of Triangle is half of //gm if they are on the same base and B/W the same parallels .we see that area of BFC is half of ABCD ____ 1 eqn

Also area of AEB = half of ABCD _____2 en.

Acc. To 1 and 2 eq

Area BFC = Area AEB

Therefore area AEB = 16cm square.

Done.......

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