In a parallelogram ABCD E and F are the mid points of side AB and CD respectively show that DP = 1/3 of DB
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solve by mid point theory and converse of mid point theory
Step-by-step explanation:
in APB ,E is mid point of AB and AE=EB -PROVED
THEREFORE PQ=BQ -1
now in DQC ,F is mid point of DC and DF=FC
:. DQ=PQ -2
FROM 1 ,2
BQ=PQ=DP
on DB
DP =1/3DB
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