Question

In a parallelogram ABCD, E and F are the mid points of sides AB and CD

respectively. Show that the line segment AF and EC trisect the diagonal BD. I need with a near explanation plz ​

Answer 1

Answer:

AE=CF

Step-by-step explanation:

GIVEN:-E and F are the mid point of sides AB and CD of the parallelogram ABCD whose diagonal is BD. AE =CF. Thus, a pair of opposite sides os a quadrilateral AECF are parallel and equal . Hence, AF and CE trisect the diagonal

Answer 2

Answer:

in this AE=CF...

Step-by-step explanation:

hope it works ✌️