In a parallelogram ABCD, E and F are the mid-points of the sides AB and
CD respectively. AF and CE meet the diagonal BD of length 12 cm at P and
Q. Then length of PQ is
a) 6 cm b) 4 cm c) 3 cm d) 5 cm
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Answer:
answer is option b) 4 cm
Step-by-step explanation:
This is because AF and CE divides diagonal BD in three equal parts as they are drawn from mid point.
thus, DP = PQ = QB......(1)
but, BD = 12cm is given
BD= DP + PQ + QB
but as per statement (1) we can say that
BD = 3* PQ
12=3*PQ
12/3= PQ
PQ = 4 cm
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