Math, asked by singhshivansh1411, 2 months ago

In a parallelogram ABCD, E and F are the mid-points of the sides AB and
CD respectively. AF and CE meet the diagonal BD of length 12 cm at P and
Q. Then length of PQ is
a) 6 cm b) 4 cm c) 3 cm d) 5 cm

Answers

Answered by someoneuseful
4

Answer:

answer is option b) 4 cm

Step-by-step explanation:

This is because AF and CE divides diagonal BD in three equal parts as they are drawn from mid point.

thus, DP = PQ = QB......(1)

but, BD = 12cm is given

BD= DP + PQ + QB

but as per statement (1) we can say that

BD = 3* PQ

12=3*PQ

12/3= PQ

PQ = 4 cm

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