Question

In a parallelogram ABCD find the measure of all the angles if one its angles is 15° less than twice
the smallest angle,​

Answer 1

Answer:

let the angles be a°, b° , c°, d°

let the smallest angle be = a

as, ∠a = ∠c     [opposite angle property]

 then, b° = 2 a -15

  as we know,

           ∠a + ∠b + ∠c +∠d = 360

           a + (2 a - 15) + a + ( 2 a - 15) = 360

           6 a - 30 = 360

            6 a = 390

          ∠ a = 65°=∠c                                                                          

    ∵ ∠a = 65

       ∠b = 130 - 15

      ∠b = 115 = ∠d

    thus the angles are 65 , 115 , 65 , 115                                                                                                

Step-by-step explanation: