Question

In a parallelogram ABCD, if ㄥA=(3x + 12)° and ㄥB=(2x -32)°,find the measure of <A and <B​

Answer 1

we know that all angel of a parallelogram is 360° and sum of 2 angel is 180 ° .

Now.

angel a +angel b = 180°

(3x+12)+(2x-32) = 180°

5x- 20= 180°

5x= 200

x = 200/5

x= 40

therefore

angle a = 3(40)+ 12= 132°

angle b = 2(40)-32= 48°

thus, angel a is 132° angle b is 48°