Question

in a parallelogram ABCD,if ∆A={3x+12)° ∆B={2x-32}° then find the value of X?​

Answer 1

Given Two angles of a parallelogram are (3x + 12) and

(2x - 32).

We know that the sum of adjacent angles of a

parallelogram is 180.

= > (3x + 12) + (2x - 32) = 180

= > 3x + 12 + 2x - 32 = 180

= > 5x - 20 = 180

= > 5x = 180 + 20

= > 5x = 200

= > x = 40.

Now,

The measure of angle A = 3x + 12

= 3(40) + 12

= 120 + 12

= 132.

The measure of angle B = 2x - 32

= 2(40) - 32

= 80 - 32

= 48.

We know that the opposite angles of a parallelogram are equal.

Hence, the measure of angle C = 132.

Hence, the measure of angle D = 48.

Therefore, the angles are A = 132, B = 48, C = 132, D = 48.

Answer 2

Answer:

x = 40

Step-by-step explanation:

according to question

[by property of parallelogram]

(3x+12) + (2x-32) = 180degree

5x - 20 = 180

5x = 180 +20

5x = 200

x = 200/5

x=40. ans