Math, asked by gautamkhudaniya10, 3 months ago

In a parallelogram ABCD, if ∠A = (3x + 12)˚, ∠B = (2x – 32)˚. Find x,

m∠ C, m∠D​

Answers

Answered by BRAINLYxKIKI
106

..Question..

In a parallelogram ABCD

if ∠A = (3x + 12)˚

∠B = (2x – 32)˚.

Find x and ∠ C and ∠D

..Answer..

Given here ,

A = ( 3x + 12 )

B = ( 2x - 32 )

☯︎ We are to find ' x '

°° We know that ,

A + B = 180

[ sum of adjacent angles is 180 ]

( 3x + 12 ) + ( 2x - 32 ) = 180

3x + 12 + 2x - 32 = 180

3x + 2x + 12 - 32 = 180

5x - 20 = 180

5x = 180 + 20

x = 200/5

x = 40

° A = ( 3x + 12 )

= ( 3 × 40 + 12 )

= ( 120 + 12 )

= 132

B = ( 2x - 32 )

= ( 2 × 40 - 32 )

= ( 80 - 32 )

= 48

Also we have to find , C and D

°° In a parallelogram , opposite sides and angles are equal.

° A = C

132 = C

C = 132

also ,

B = D

48 = D

D = 48

____________________

Give a look here ,

  • angle sum property of triangle = 180
  • angle sum property of quadrilateral = 360
  • sum of 2 adjacent angles = 180
  • Linear pair = 180

ʙʀɪɴʟʏ×ɪɪ

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