Question

In a parallelogram ABCD, if A = 65° then find each of the angles of the parelleogram​

Answer 1

$\huge{\green{\underline{\underline{\mathfrak{\diamond\; Solution:}}}}}$

Given,

ABCD is a Parallelogram

Angle A = 65°

$☆\;\boxed{\sf{In\;a\; Parallelogram\; Opposite\;Angles\;are\; Equal}}$

So, Angle A = Angle D

Angle B = Angle C

$☆\;{\boxed{\sf{In\;a\; Parallelogram\; Adjacent\;Angles\;are\; Supplementary}}}$

So, Angle A+Angle B = 180°

Angle C+Angle D = 180°

Now,

$→\;{\bf{Angle\;A+Angle\;B = 180°}}$

$→\;{\bf{65°+Angle\;B = 180°}}$

$→\;{\bf{Angle\;B = 180°-65°}}$

$➝\;{\tt{Angle\;B = 115°}}$

As, Angle A = Angle D

◕➜ Angle D = 65°

As, Angle B = Angle C

◕➜ Angle C = 115°

Hope It Helps You ✌️

Answer 2

Answer:

yes the answer is right of