Question

in a parallelogram ABCD if AD=10cm CF=8cm and BG =12cm find AB​

Answer 1

Answer:

AD IS DIAGNOL AND DIGNOLS OF || GRAM WILL BE EQUAL AND THEY INTESECT AT THEIR MID POINT WITH ANGLE 90° √25+25=√50=5√2

Answer 2

$\underline\mathfrak{Given}\\\\\\\sf {In \: ABCD \: parallelogram \\\\AD = 10\:cm ,\:BG = 12\:cm \\CF=10\:cm,\:AB=?\\\\\boxed {Area\:of \: a \: parallelogram \\= base \times corresponding\: height} \\\\ Here, \\\\Area \: of \: parallelogram \:ABCD = AD \times BG --(1) Area \: of \: parallelogram \:ABCD = AB \times CF --(2)}$

$\sf {10\:cm \times 12\:cm = AB \times 8\:cm\\\\\\ \implies \frac{120}{8}=AB\\\\\implies 15 \:cm = AB}$