Question

In a parallelogram ABCD, If angale A = (3x + 12), Angele
B = (2x - 32)º then find the value of x​

Answer 1

Answer:

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Answer 2

$given \: ABCD \: is \: a \: parallelogram \: \\ we \: know \:that \: 2 \: angles \: on \: the \: same \: \\ side \: is \: = {180}^{0} \\ \\ therefore \: \: \: \\ 3x + 12⁰ + 2x - 32⁰ = 180 ⁰ \\ 5x - 20 ⁰= 180⁰ \\ 5x = 180⁰ - 20⁰ \\ 5x = 160⁰ \\ x = \frac{160⁰}{5} \\ x = 32⁰$

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