In a parallelogram ABCD, if angle A = (3x + 12)° angle B = (2x - 32)° then find the value of x and then find the measure of angle C and angle D
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the corresponding angle are supplement so x=40
manasvi7:
but angle a and angle b
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(3x+ 12)* + (2x-32)* = 180 ( OPP SIDE OF Parallelogram)
5x - 20 = 180
5x= 200
x = 40
Angle A= 3*40 + 12= 132
B= 2*40- 32= 48
C= 132
D = 48
5x - 20 = 180
5x= 200
x = 40
Angle A= 3*40 + 12= 132
B= 2*40- 32= 48
C= 132
D = 48
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