In a parallelogram ABCD, if angle A =(3x+12)°and B=(2x -32)° then find the value of x and measures of angle C and angle D
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3x+12+3x+12+2x-32+2x-32=360
10x-40=360
10x=400
x=40
c=3*40+12=132
d=80-32=48
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