Math, asked by shwetautekar, 4 months ago

In a parallelogram ABCD, if angle A =(3x+12)°and B=(2x -32)° then find the value of x and measures of angle C and angle D

Answers

Answered by cgrgopalreddy4888

2

Answer:

3x+12+3x+12+2x-32+2x-32=360

10x-40=360

10x=400

x=40

c=3*40+12=132

d=80-32=48

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