Question

in a parallelogram ABCD, if angle A=(3x+12), angle B=(2x-32) then find the value of x find the meusures of angle A?​

Answer 1

Step-by-step explanation:

IN A PARALLELOGRAM OPPOSITE ANGLES ARE EAUAL

A=D

B=C

AND ALL ANGLES IN A PARALLELOGRAM SUM UP TO 360°

THEREFORE

A+B+C+D=360°

3x+12+2x-32+3x+12+2x-32=360°

10x-40=360°

10x=360°+40

10x=400°

x=400/10

x=40°

NOW SUBSTITUTE X VALUE IN ALL ANGLES

A=D=3x+12

=3(40)+12

=120+12

=132°

B=C=2x-32

2(40)-32

=80-32

=48°

THERFORE X=40° AND ANGLE A= 132°