in a parallelogram ABCD if angle C= 65 then find measure of (angle B+ angle D )
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Let ABCD be a parallelogram in which ∠A=65∘.
Since AD∥BC we can treat AB as a transversal. So,
∠A+∠B=180∘
65∘+∠B=180∘
∠B=180∘−65∘
∠B=115∘
Since the opposite angles of a parallelogram are equal, we have
∠C=∠A=65∘ and ∠D=∠B=115∘
Hence, ∠B=115∘,∠C=65∘ and ∠D=115∘

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