In a parallelogram abcd, if angle dab=75 and angle dbc=60 then find angle bdc
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∠BDC = 45° if In a parallelogram abcd, if angle dab=75 and angle dbc=60
Step-by-step explanation:
In a parallelogram abcd, angle dab=75
∠DAB = 75°
in a parallelogram opposite angles are equal
=> ∠DCB = 75°
∠DBC = 60° ( given)
∠BDC = ?
in Δ BCD
sum of angles of a triangle = 180°
∠DCB + ∠DBC + ∠BDC = 180°
75° + 60° + ∠BDC = 180°
=> ∠BDC = 45°
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