Question

In a parallelogram ABCD if angle DAB = 75°
and angle DBC = 60°, find angle CDB and angle ADB.
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Answer 1

Answer:

It is given that <DAB = 75° and <DBC = 60°

Since ABCD is a parallelogram, opposite angles are equal

<DAB = <BCD and <ADC = <ABC

Therefore <DAB + <BCD = 75 + 75 = 150°

To find <ADB

<ADB = <DBC (alternate interior angle)

therefore <ADB = 60°

To find <CDB

<ADC + <ABC = 360 - 150 = 210

<ADC= 105 and <ABC = 105

<ABC = <ABD+ <CBD

<ABD = 105 - 60 = 45°

<ABD= <CDB = 45° (alternate interior angle)

<CDB = 45°

HOPE IT HELPS :)

Answer 2

Answer:

Step-by-step explanation:

BCD=DAB=75

CDB=180-DBC-BCD=180-75-60=45

ADB=DBC=60