in a parallelogram ABCD if angle DAB is 75 degree angle DBC is 60 degree find angle CDB and angle ADB
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In ||gm, ∠DCB = ∠DAB = 75° (Opposite angles of parallelogram are equal) In ∆DCB, ∠DBC + ∠DCB + ∠CDB = 180° 60° + 75° + ∠CDB = 180° ∠CDB = 180 ° – 135° = 45° Read more on Sarthaks.com - https://www.sarthaks.com/857845/in-a-parallelogram-abcd-if-dab-75-dbc-60-then-find-cdb
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