in a parallelogram ABCD if angle Dab is equal to 75 degree and Angle DBC is equal to 60 degrees then angle bdc equal to (ntse)
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Hey mate...here is ur ans...☺☺✌
We know that in a parallelogrm the sum of adjacent and opposite angles = 180°
So <DAB + <DBC + <ABD = 180°
75° + 60° + <ABD = 180
<ABD = 180 - 135
<ABD = 45°
Now, ABC = 45° + 60° = 105°
Again, <ABC + <BCD = 180°
105° + <BCD = 180°
<BCD = 180°-105°
<BCD = 75°
Now In triangle BDC
<BCD + <BDC + <DBC = 180°
75° + 60° + <BDC = 180°
<BDC = 180°-135°
<BDC = 45°
✔So <BDC = 45°
Hope it helps u...thanks...☺☺✌
We know that in a parallelogrm the sum of adjacent and opposite angles = 180°
So <DAB + <DBC + <ABD = 180°
75° + 60° + <ABD = 180
<ABD = 180 - 135
<ABD = 45°
Now, ABC = 45° + 60° = 105°
Again, <ABC + <BCD = 180°
105° + <BCD = 180°
<BCD = 180°-105°
<BCD = 75°
Now In triangle BDC
<BCD + <BDC + <DBC = 180°
75° + 60° + <BDC = 180°
<BDC = 180°-135°
<BDC = 45°
✔So <BDC = 45°
Hope it helps u...thanks...☺☺✌
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