Math, asked by fariyakhan037037, 1 year ago

in a parallelogram ABCD,if angleA=(3x+12)degree,angleB=(2x-32)degree then find the value of x and then find the measure of angle c and angle d​

Answers

Answered by sonabrainly
7

Answer:

Step-by-step explanation:

(3x + 12) + (2x - 32) = 180

3x + 12 + 2x - 32 = 180

5x - 20 = 180

5x = 180 + 20

5x = 200

x = 40.

Now,

The measure of angle A = 3x + 12

                                        = 3(40) + 12

                                        = 120 + 12

                                        = 132.

The measure of angle B = 2x - 32

                                         = 2(40) - 32

                                         = 80 - 32

                                         = 48.

Answered by swamy950544
1

Answer:

sum of all angles in parallelogram =360 and corresponding angles sum =180

Step-by-step explanation:

therefore,

(3x+12)+(2x-32)=180

3x+2x+12-32=180

5x-20=180

x=200÷5

x=40 degrees

angle A =3×40+12=132

keep it up

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