in a parallelogram ABCD,if angleA=(3x+12)degree,angleB=(2x-32)degree then find the value of x and then find the measure of angle c and angle d
Answers
Answered by
7
Answer:
Step-by-step explanation:
(3x + 12) + (2x - 32) = 180
3x + 12 + 2x - 32 = 180
5x - 20 = 180
5x = 180 + 20
5x = 200
x = 40.
Now,
The measure of angle A = 3x + 12
= 3(40) + 12
= 120 + 12
= 132.
The measure of angle B = 2x - 32
= 2(40) - 32
= 80 - 32
= 48.
Answered by
1
Answer:
sum of all angles in parallelogram =360 and corresponding angles sum =180
Step-by-step explanation:
therefore,
(3x+12)+(2x-32)=180
3x+2x+12-32=180
5x-20=180
x=200÷5
x=40 degrees
angle A =3×40+12=132
keep it up
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