In a parallelogram ABCD if m ∠A = ( 3x – 12 )° and m ∠B = (2x – 32 )°
then find the value of x
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∠A=3x+12
∠B=2x−32
Now sum of adjacent angles of a parallelogram is 180.
⇒3x+12+2x−32=180
⇒5x−20=180
⇒5x=200
⇒x=40
∠A=3(40)+12=132
∠B=2(40)−32=48
Now opposite angles in a parallelogram are equal
⇒∠A=∠C and ∠B=∠D
∴∠C=132 and ∠D=48.
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