In a parallelogram ABCD if two diagonals are equal. Find the measure of angle ABC.
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Since ABCD is a parallelogram .
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★ Therefore AB = CD And AD = BC
Thus in ∆ ABD and ∆ ACB ,
★ AD = BC
★ BD = AC
★ AB = AB
So by SSS criteria of Congruence ,
∆ABD ≈ ACB
Therefore , Angle BAD = Angle ABC
Now AD || BC and Transversal AB intersects them at AB respectively .
Therefore ,
Angle BAD + Angle ABC = 180°
Angle ABC + Angle ABC = 180°
2 ( ABC ) = 180°
Angle ABC = 90°
★ Answer = 90°
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