In a parallelogram ABCD, ifangle A =(3x+12)°, angle B=(2x-32)°then find the value of x and then find the measures of angle C and angle D
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(3x+ 12)* + (2x-32)* = 180 ( OPP SIDE OF Parallelogram)
5x - 20 = 180
5x=200
x= 40
Angle A= 3 x 40 + 12= 132
B= 2 x 40-32= 48
C= 132
D = 48
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