Question

In a parallelogram ABCD, ifangle A =(3x+12)°, angle B=(2x-32)°then find the value of x and then find the measures of angle C and angle D ​

Answer 1

Answer:

(3x+ 12)* + (2x-32)* = 180 ( OPP SIDE OF Parallelogram)

5x - 20 = 180

5x=200

x= 40

Angle A= 3 x 40 + 12= 132

B= 2 x 40-32= 48

C= 132

D = 48