in a parallelogram ABCD it's diagonal AC and BE intersect at O if AO =5cm then AC=
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Given,
A parallelogram ABCD
AC and BD intersect at o
AO=5 cm
To find,
Value of AC
ATQ,
As we know that diagonals of a parallelogram are the bisectors of each other
So,
AO=AC/2
5=AC/2
AC=5*2
AC=10 cm
Hope this helps you!
A parallelogram ABCD
AC and BD intersect at o
AO=5 cm
To find,
Value of AC
ATQ,
As we know that diagonals of a parallelogram are the bisectors of each other
So,
AO=AC/2
5=AC/2
AC=5*2
AC=10 cm
Hope this helps you!
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