Question

In a parallelogram ABCD length of AB – CD is equal to​

Answer 1

Answer:

Let AC and BD intersect at O.

∴DO is the median of triangle ADC

Using Apollonius' theorem inΔADC, we get

⇒AD

2

+CD

2

=2((AO)

2

+(DO)

2

)=AD

2

+(4)

2

=2((2)

2

+(3)

2

)

⇒AD

2

+16=2(4+9)=26

⇒AD

2

+16=2(4+9)=26

AD=

10

=BC