Question

In a parallelogram Abcd ,<ABC =110°,Find the other angles of the parallelogram


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Answer 1

Given ∠A = 110o But we know that sum of adjacent angles of a parallelogram is 180o ∠A + ∠B = 180o 110o+ ∠B = 180o ∠B = 180o– 110o= 70o. Also ∠B + ∠C = 180o [Since ∠B and ∠C are adjacent angles] 70o+ ∠C = 180o ∠C = 180o– 70o= 110o. Now ∠C + ∠D = 180o [Since ∠C and ∠D are adjacent angles] 110o+ ∠D = 180o ∠D = 180o– 110o= 70o

Answer 2

Answer:

In a parallelogram ABCD,

<A = <C = 110

and

<B = <D = 70

Step-by-step explanation:

Given ABCD is a parallelogram

and

<A = 110 ------ (1)

/* Sum of adjacent angles are

supplementary in a parallelogram*/

<A + <B = 180

=> 110 + < B = 180

=> <B = 180 - 110

=> <B = 70------ (2)

/* In a parallelogram,

opposite angles are equal */

Therefore,

In a parallelogram ABCD,

<A = < C = 110

and

<B = < D = 70

....