Math, asked by anishmanisingh2, 9 months ago

In a parallelogram ABCD P is a point on CD in such a way that AD = DP = PC (As shown in
figure). Prove that
(i) AP bisects ZDAB
(ii) ZCBP + ZDAP = ZAPB

Attachments:

Answers

Answered by sakshi1907

0

Step-by-step explanation:

where is 'Z'how we will find the ans there in no point Z in the fig

Previous Question

Next Question

Similar questions

Social Sciences, 4 months ago

vikendrikaran kya h...

Social Sciences, 4 months ago

plz tell is planting forest A good thing...

English, 4 months ago

Tom splashed the pizza with cheese and sauce of every kind,He thought it would be tastier to add all he could find. He loaded up the top, with meats and vegetables galore, And piled all he could, till the base was visible no more. Q1. = what did Tom to do make pizza tastier...

English, 9 months ago

PLEASE ANSWER THIS QUESTION... In some of the sentence given below "much" is incorrect or unnatural. change "much" to "many" or "a lot of" whenever necessary. put 'Right' if the sentence is correct. the first two have been done for you. e) She'll have to hurry. she hasn't got much time.

Economy, 9 months ago

17. NAME THE OTHER MOST COMMON ACTIVITY IN PALAMPUR OTHER THAN FARMING. *...

Math, 1 year ago

please answer the above question...

Math, 1 year ago

determinate which letter best answers each question...

Math, 1 year ago

(ii) If x means +, - means -, - means x and + means - then 8 + 7 * 8 / 40 -2 =?