IN A PARALLELOGRAM ABCD , P IS A POINT ON CD IN SUCH A WAY THAT AD=DP=PC . PROVE THAT AP BISECTS ANGLE DAB ANGLE CBP +ANGLE DAB= ANGLE APB
Answers
Answered by
0
Answer:
n a parallelogram ABCD P is a point on CD in such a way that AD = DP = PC (As shown in
figure). Prove that
(1) AP bisects angleDAB
(ii) angleCBP + angleDAP = angle
APB
Answered by
1
Answer:
,hope this will help you plz follow me and add the answer to Brainliest answers and 10 thanks plz
Attachments:
Similar questions