In a parallelogram ABCD, P is a point on
side AD such that 3AP = AD and Q is a
point on BC such that 3CQ BC. Prove
that : AQCP is a parallelogram.
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Answer:
It is given that ABCD is a parallelogram.
In which AD//BC and also AD = BC
and AB//CD and AB = CD
NOW,
3AP = AD and AD = BC
So, 3AP = BC
Same with 3CQ= BC
THEREFORE
AQCP is //gram
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