In a parallelogram ABCD the angles A and C are obtuse. Points X and Y are taken on the diagonal BD such that the angles angle XAD and angle YCB are right angles. Prove that XA =YC.
students78:
please give me my answer
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Dear Student!
Here is the answer to your query.
Given : ABCD is a parallelogram and AX and CY are perpendicular on diagonal BD
Now In ∆ABX and ∆CDY
⇒ ∠AXB = ∠CDY = 90° (Given)
and ∠ABX = ∠CDY (Alternate opposite angles)
AB = CD (opposite sides of a ||gm)
∆ABX ≅ ∆CDY (by AAS congruency criterion)
⇒ AX = CY (C.P.C.T.)
Here is the answer to your query.
Given : ABCD is a parallelogram and AX and CY are perpendicular on diagonal BD
Now In ∆ABX and ∆CDY
⇒ ∠AXB = ∠CDY = 90° (Given)
and ∠ABX = ∠CDY (Alternate opposite angles)
AB = CD (opposite sides of a ||gm)
∆ABX ≅ ∆CDY (by AAS congruency criterion)
⇒ AX = CY (C.P.C.T.)
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