Math, asked by harshyadav4dec, 1 year ago

In a parallelogram ABCD the bisector of angle A and Angle B meet at point O find angle aob

Answers

Answered by Henrico

5

angle A + Angle B equals to 180 (co interior angles )
1/2A+1/2B=1/2(180)
oab+oba=90
in triangle Oab
oba+oab+aob=180
aob+90=180
aob=90

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