In a parallelogram ABCD the bisector of angle A and Angle B meet at point O find angle aob
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so angle aob =1/2 of 90 so 30 answer
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angle A +angle B = 180 (co interior)
1/2A +1/2B =1/2(180)
oab +oba = 90 now
oab+ oba +aob =180
90+aob= 180
aob=90
1/2A +1/2B =1/2(180)
oab +oba = 90 now
oab+ oba +aob =180
90+aob= 180
aob=90
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