Math, asked by jayapaul985, 8 months ago

In a parallelogram ABCD, the bisector of angle ABC intersects AD at P. If PD = 5, BP = 6 and
CP = 6, find AB
(A) 5
(B) 4
(C) 6
(D) 8​

Answers

Answered by Gauravmavi7
1

Step-by-step explanation:

Answer:  Step-by-step explanation: ABCD.     ⇅.                         Angle abc bisector ( bisect means to cut into 2 parts equally and exactly)  So it means the line intersect AD at P   Pd-5 cm                                                                                                                .   BP-6 cm  CP-6 cm  Find AB IN CENTIMETERS    Method 1. :     BP And CP -6 cm  PD-5 cm  If PD-5 cm, then PB,PA,PC are 5 cm since p is same length as p and p is the point where they meet so all P are equal .  Here it is simple  ( I already worked out the question two times and got the same answer on calculator )  Sides of parallelogram is BP , CP and the two unknown were DA , AD and AP , AB   If BP -6 so CP -6  If PD- 5 then PA-5 6+6= 12 cm  5+5= 10 cm  Thus , 12+ 10 cm= 22 cm _ > perimeter  6+6+6+6=24  5+5+5+5=20  This is the final and right answer= 24+ 20 cm = 44 cm  Parallelogram has four sides  44 divide by 4 = 11   Answer = 11 cm           Now I will explain to u in simple method 2  PA 5 cm , PD 5 cm  BP 6 cm , CP 6 cm    Trick : PA+ BP or PD+ CP = 5cm + 6 cm = 11 cm

Similar questions