In a parallelogram ABCD the bisectors if A also bisects BC at x. If Ad =10cm, Find the value of AB.
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Let
The b isectorof∠Ab isectsthesideBCatx.
Given;−ABCDisp a r a l l e o g r a m
∴AD∥BC
Now,AXisthetransversal
∴∠1=∠3(alternateangles)−−−−(1)
and∠1=∠2(AXistheb isectorof∠A)−−(2)
From(1)and(2)weget
∠1=∠3
Now,
InΔABX
∠1=∠3
⇒A B=BX
⇒2 A B=2BX=BX+BX=BX+XC(XisthemidpointsofBC)
⇒2 A B=BC
⇒2 A B=AD(oppositesideofaparallelogramareequal)
∴AD=2 A B
proved.
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