Math, asked by atharv1132006, 1 year ago

In a parallelogram ABCD, the bisectors of angle A and angle B meet at O.Then angle AOB is equal to
options
a)85°
B)90°
c)45°
d) none of these​

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Answers

Answered by atharva5976
4

Answer:

90 degree

Step-by-step explanation:

According to the propeties

of parallelogram the the line which bisect the any angle of parallelogram is equals to 45 degrees

so angle OAB and angle OBA is equally to 45 degrees respectively

now add bother the angles

then the sum will be 90 degrees

now angle AOB + angle OAB +angle OBA=180 degree

so 45 +45+angle AOB =180 degrees

now angle AOB = 180-45+45

so AOB =180-90

AOB =90 degrees

Answered by harshita5619
1

Answer:

90 Is answer Bisectors intersect at O

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