Question

In a parallelogram ABCD, the diagonals intersect at O. Prove that OA = OB and BO= DO. ​

Answer 1

Answer:

∵ When diagonal AC and BD intersect each other at point O,

then OA = OC = (1/2) AC

And OB = OD = (1/2) BD

∴ OA = 1/2 × AC ⇒ AC = 2 × OA

⇒ AC = 2 × 6 cm = 12 cm,

And OB = 1/2 × BD ⇒ BD = 2 × OB

⇒ BD = 2 × 7.5 ⇒ BD = 15 cm