Question

in a parallelogram ABCD the measure of angle A exceeds the measure of Angle B by 20 degree find the measure of angle A and Angle B

Answer 1

let angle B be x then angle A=x+20
the sum of angle A and B will be 180
therefore,x+ x+20=180
2x=180-20
x=160/2
x=80
therefore,angle B=80 and Angle B=80+20=100degree

Answer 2

Let Angle A be x
and Angle B be x+20
Angle A + Angle B = 180 degree
So, x + x + 20 = 180 degree
2x +20 =180
2x=180-20
2x = 160
x =160÷2
x= 80
Hence, Angle A is x = 80 degrees
Angle B is x + 20 = 100 degree
Hope this helped you!