Question

in a parallelogram abcd, the sides dc is produced to e and <bce =105°. caculate <a <b <c and <d.​

Answer 1

Answer:

The angles ∠A, ∠B, ∠C, ∠D are75, 105, 75,

105

Step-by-step explanation:

From the figure, we can say that

∠BCE + ∠BCD = 180 (Since ∠DCE is the straight angle)

By substituting the values we get,

⇒ 105 + ∠BCD = 180

⇒ ∠BCD = 180 - 105

⇒ ∠BCD = 75

We know in a parallelogram the opposite angles are equal and the sum of the adjacent angles is 1800.

i.e, ∠C = ∠A ...... (1)

∠B = ∠D ...... (2)

∠C + ∠D = 180 ...... (3)

From Eq(1) we can write

∠A = 75

From Eq(3), we can write

⇒ 75+ ∠D = 180

⇒ ∠D = 180 - 75

⇒ ∠D = 105

From Eq(2), we can write

∠B = 105

The angles ∠A, ∠B, ∠C, ∠D are75, 105, 75,

105.

Answer 2

Reason: Linear pair

Substituting the values

105+<C=180

105+∠C=180

< C=180-105=75

∠C=180−105=75∘

Angle C+angle B=180 degrees

hence , <B = <BCE

<B = <D

so, = 105.

<A. = <C

so , = 75

thanks

mark brainliest

@ film it now