Question

in a parallelogram ABCD two points p and q are the take on diagonal BD such that DP is equal to BQ show that triangle APD is congruent to triangle cqb. second ap is equal to CQ. third triangle A Q B is congruent to triangle CPD. 4th a q is equal CP. 5th APCQ is a parallelogram​

Answer 1

Answer:

Step-by-step explanation:in triangle apd and cqd

dp=bq

ad=bc(opp. sides of a parallelogram)

angle pda=angle qbc (alternate interior angle)

by sas congruence apd≅cqb

by cpct ap=cq

Answer 2

Step-by-step explanation:

This is your answer

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