In a parallelogram ABCD whose vertices are taken in order, if ∠A=40°∠A=40° , then ∠D=
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ABCD is a parallelogram
Given ∠DAB=∠BCD=40
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and AD∥BC
We know that sum of consecutive angle are 180
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∠CBA+∠DAB=180
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∴∠CBA=180−40=140
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We know that in parallelogram opposite angles are equal
Then ∠ADC=∠CBA=140
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So angles of parallelogram are 40
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,140
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,40
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,140
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