In a parallelogram angle A : angle B = 1:2then angle A is
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the parallelogram is ABCD
we know that the opposite angles of a parallelogram are equal. so,
/_ A = /_ C
and /_ B = /_ D
we have angle A = angle C =1x and angle B = angle D = 2x
we know that sum of all angles of a quadrilateral is 360 degree, so
angle A + angle B +angle C +angle D= 360
1x +2x +1x +2x = 360
6x = 360
x = 60 degree
angle A = 60 degree.
hence proved
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we know that the opposite angles of a parallelogram are equal. so,
/_ A = /_ C
and /_ B = /_ D
we have angle A = angle C =1x and angle B = angle D = 2x
we know that sum of all angles of a quadrilateral is 360 degree, so
angle A + angle B +angle C +angle D= 360
1x +2x +1x +2x = 360
6x = 360
x = 60 degree
angle A = 60 degree.
hence proved
plz mark as brainliest
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Answered by
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We know that:
In a parallelogram the sum of adjacent angles is 180°.
angle A+angle B=180°
Let the ratio be x.
1x+2x=180°
→3x=180°
→x=180°/3
→x=60°.
angle A=1x=60°.
In a parallelogram the sum of adjacent angles is 180°.
angle A+angle B=180°
Let the ratio be x.
1x+2x=180°
→3x=180°
→x=180°/3
→x=60°.
angle A=1x=60°.
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