Question

In a parallelogram angle Q(4x-5)° &angle s=(3x+10)calculate the angle Q and angle R

Answer 1

we know,

opposite angles of a parallelogram are equal..

therefore, angle Q = angle S

→4x -5= 3x +10

→4x -3x = 10+5

→x= 15°

.

. . angle Q= 4x-5 = 4×15-5= 55°

also, we know,

adjacent angles of a parallelogram are equal..

therefore angle Q+angle R=180°

angle R=180 - 55

= 125°

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