Question

In a parallelogram area is equals to 132 CM square and base is equals to 11 cm B if a triangle area is equals to 132 CM square and base is equals to 11 cm find the altitude of the both

Answer 1

Step-by-step explanation:

• area of 11qm is b x h
• area of 11qm is 132 cm sq
• base is 11 cm
• altitude will be 132 / 11= 12 cm

• area of triangle= 132 cm sq
• =1/2*b*h
• base = 11cm
• = 1/2*11*h=132cm
• = 11h=132*2
• = 11h=264
• =h = 264/11
• =h=24cm

thus altitude of parallelogram will be 12 cm and altitude of triangle will be 24 cm.

Answer 2

Answer:

area of parallelogram=b×h--1

therefore,base=11cm

area=132cm

and from eq.1

132=11×h

h=132/11=12

therefore height of parallelogram is equal to 12

then,area of triangle =1/2×b×h-----2

and b=11. area=132

from eq2

132=1÷2×11×h

132×2×1/11=h

12×2=h

h=24

therefore height of triangle is 24