In a parallelogram, it's diagonals are perpendicular to each other Can we conclude that the parallelogram is a rhombus? Explain
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Since the diagonals of a parallelogram bisect each other,
BE and DE are congruent and AE is congruent to itself.
We are given that diagonals are perpendicular henceforth all four angles at point E are 90 °and are therefore congruent.
Triangles ABE and ADE are congruent by side-angle-side,
Therefore, AB and AD are congruent.
Since opposite sides of a parallelogram are congruent,
AD and BC are congruent, and AB and CD are congruent.
So all four sides are congruent.
Hence, ABCD is a rhombus.
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