Math, asked by hatwangrangsu, 3 months ago

in a parallelogram king , if m<I =60° find all the other angles​

Answers

Answered by Anonymous
4

In parallelogram KLMN, ∠K=60

[Given]

⇒ ∠K=∠M [Opposite angles of parallelogram are equal]

⇒ So, ∠K=∠M=60

---- ( 1 )

⇒ ∠K+∠N=180

[Sum of adjacent angles of parallelogram is supplementary]

⇒ 60

+∠N=180

∴ ∠N=120

⇒ ∠N=∠L [Opposite angles of parallelogram are equal]

⇒ So, ∠N=∠L=120

---- ( 2 )

From ( 1 ) and ( 2 ) we get,

∠K=60

,∠L=120

,∠M=60

and∠N=120

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Answered by anjumanyasmin
0

Given:

parallelogram KING

m<I =60°

Then, solve that,

∠K=?

∠N=?

∠G=?

We know that,

Adjacent angles of parallelogram is supplementary.

Then,

∠K+∠I=180°

∠K + 60°= 180°

∠K = 180° - 60°

∠K=120°

know that,  Opposite angles of parallelogram are equal.

Then,

∠K=∠N

120°= ∠N

And

∠I=∠G

∠G=60°

Hence in a parallelogram KING angles are  ∠K=120°, 120°= ∠N , ∠I=60° and ∠G=60°

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