Question

In a parallelogram one angle is 4/5th of the adjacent angle. determine the angles of parallelogram

Answer 1

Let the first angle be x and the second angle be y.
Then x = 4y/5
5x = 4y
5x - 4y = 0 ......(1)
Also x + y = 180° .......(2)
Multiply eq (2) by 5
Then 5x + 5y = 900° ......(3)
(3) - (1) we get
9y = 900°
y = 100°
Put this value in eq (2)
x + 100° = 180°
x = 180° - 100°
x = 80°
Therefore, the angles are 80°, 100°, 80°, 100° because in a parallelogram opposite angles are equal.
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Answer 2

Answer:

Step-by-step explanation:

Let the first angle be x and the second angle be y.

Then x = 4y/5

5x = 4y

5x - 4y = 0 ......(1)

Also x + y = 180° .......(2)

Multiply eq (2) by 5

Then 5x + 5y = 900° ......(3)

(3) - (1) we get

9y = 900°

y = 100°

Put this value in eq (2)

x + 100° = 180°

x = 180° - 100°

x = 80°

Therefore, the angles are 80°, 100°, 80°, 100° because in a parallelogram opposite angles are equal.

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