Question

In a parallelogram, PQRS, angle. P= (2x +10°)angle R= (3x - 20) .Find the value of x.​

Answer 1

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Answer 2

The value of x is

${34}^{o}$

Given

$∠ P = {(2x + 10)}^{o}$

∠ Q = (3x - 20)

From the given we can say that ∠ P and ∠ R are opposite to one another , hence parallel to each other.

If they are parallel their angle is

${90}^{o} \: \: each$

so,

$∠ P + ∠ R = {180}^{o}$

$= (2x + {10}^{o} ) + (3x - {20}^{o} ) = {180}^{o} \\ = 2x + 10 + 3x - 20 = {180}^{o} \\ = 5x - 10 = {180}^{o} \\ = 5x = 180 - 10 \\ = 5x = 170 \\ = x = 170 \div 5 \\ =x = {34}^{o}$

Therefore

In a parallelogram, PQRS, angle. P= (2x +10°)angle R= (3x - 20) the value of x is

${34}^{o}$